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40
qsort.h
40
qsort.h
@@ -42,4 +42,44 @@ else
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return parity;
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}
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template<typename INDEX>
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int genqsort2(INDEX l, INDEX r, bool (*bigger)(const INDEX, const INDEX), void (*swap)(const INDEX,const INDEX))
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{
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INDEX i,j,piv;
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int parity=0;
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if(r<=l) return parity; //1 element
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if(bigger(l,r)) {parity^=1; swap(l,r);}
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if(r-l==1) return parity; //2 elements and preparation for median
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piv= (l+r)/2; //pivoting by median of 3 - safer
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if(bigger(l,piv)) {parity^=1; swap(l,piv);} //and change the pivot element implicitly
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if(bigger(piv,r)) {parity^=1; swap(r,piv);} //and change the pivot element implicitly
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if(r-l==2) return parity; //in the case of 3 elements we are finished too
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//general case , l-th r-th already processed
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i=l+1; j=r-1;
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do{
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//important sharp inequality - stops at sentinel element for efficiency
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// this is inefficient if all keys are equal - unnecessary n log n swaps are done, but we assume that it is atypical input
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while(bigger(piv,i++));
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i--;
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while(bigger(j--,piv));
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j++;
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if(i<j)
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{
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// swap and keep track of position of pivoting element
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parity^=1; swap(i,j);
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if(i==piv) piv=j; else if(j==piv) piv=i;
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}
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if(i<=j) {i++; j--;}
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}while(i<=j);
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if(j-l < r-i) //because of the stack in bad case process first the shorter subarray
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{if(l<j) parity ^=genqsort2(l,j,bigger,swap); if(i<r) parity ^=genqsort2(i,r,bigger,swap);}
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else
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{if(i<r) parity ^=genqsort2(i,r,bigger,swap); if(l<j) parity ^=genqsort2(l,j,bigger,swap);}
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return parity;
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}
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#endif
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